35=-16x^2+72x+5

Solution for 35=-16x^2+72x+5 equation:

35=-16x^2+72x+5

We move all terms to the left:

35-(-16x^2+72x+5)=0

We get rid of parentheses

16x^2-72x-5+35=0

We add all the numbers together, and all the variables

16x^2-72x+30=0

a = 16; b = -72; c = +30;
Δ = b2-4ac
Δ = -722-4·16·30
Δ = 3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3264}=\sqrt{64*51}=\sqrt{64}*\sqrt{51}=8\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-8\sqrt{51}}{2*16}=\frac{72-8\sqrt{51}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+8\sqrt{51}}{2*16}=\frac{72+8\sqrt{51}}{32}
$